Aluminum reacts with excess hydrochloric acid to form aqueous aluminum chloride and 31.0 mL of hydrogen gas ov? - form 31 earnest money promissory note
Aluminum reacts with excess hydrochloric acid aqueous aluminum chloride and 31.0 ml of hydrogen from water to 27 ° C to form 735 mm Hg. How many grams of aluminum reacted?
Sunday, February 7, 2010
Form 31 Earnest Money Promissory Note Aluminum Reacts With Excess Hydrochloric Acid To Form Aqueous Aluminum Chloride And 31.0 ML Of Hydrogen Gas Ov?
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PV = nRT
n = PV / RT = moles H2
P = 735 mm Hg x (1 atm / 760 mmHg) = 0.967 atm
V = 0.0310 L
R = 0.0821 LATM / molecule
T = 27 C = 27 273 = 300 K
n = (0.967 atm) x (0.0310 L) / [(0.0821 LATM / molecule) x (300 K)]
n = 0.001217 mol H2
2 Al + 6 HCl ----> 2 AlCl 3 + 3 H2 (g)
the balanced equation 2 moles of Al ---> 3 mol H2
0.001217 mol H2 x (2 mol Al / 3 moles H2) = 0.000811 moles Al
Finally ...
0.000811 moles Al x (27.0 g / mol) = 0.0219 g Al
PV = nRT
n = PV / RT = moles H2
P = 735 mm Hg x (1 atm / 760 mmHg) = 0.967 atm
V = 0.0310 L
R = 0.0821 LATM / molecule
T = 27 C = 27 273 = 300 K
n = (0.967 atm) x (0.0310 L) / [(0.0821 LATM / molecule) x (300 K)]
n = 0.001217 mol H2
2 Al + 6 HCl ----> 2 AlCl 3 + 3 H2 (g)
the balanced equation 2 moles of Al ---> 3 mol H2
0.001217 mol H2 x (2 mol Al / 3 moles H2) = 0.000811 moles Al
Finally ...
0.000811 moles Al x (27.0 g / mol) = 0.0219 g Al
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